Spring Calibration Data -> Need to figure out formula

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SUMMARY

The discussion centers on calculating the expected slope of a line related to spring calibration data, specifically using the formula ac = rω². The expected slope is defined as –4π²(µ/g)(Mg/k), with known values of (Mg/k) = 5.3 and µ = 5. The user is uncertain about the value of g, speculating it to be either 9.8 or -9.8, but both calculations yield incorrect results of 106.753 or -106.753. The need for clarification on the correct value of g is emphasized.

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  • Understanding of spring dynamics and calibration principles
  • Familiarity with the concepts of angular acceleration and linear motion
  • Knowledge of basic physics formulas involving gravitational acceleration
  • Proficiency in algebraic manipulation of equations
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mcdowellmg
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Spring Calibration Data --> Need to figure out formula

I feel like every time I post a problem here, I end up figuring it out. So, thanks for that! haha
 
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Another question. I am supposed to find the expected slope of a line that will help me realize that ac = rω2.

expected slope = –4*pi^2(µ/g)(Mg/k) =

I know that (Mg/k) = 5.3. I know that µ = 5. I am GUESSING that g = 9.8 or -9.8, but both of the answers 106.753 or -106.753 are not correct. I cannot figure this out, so thanks for any help!
 

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