$$x^{2}+1 \neq n! $$since $$x^{2}+1=(x+i)(x-i) $$so ,$$ x^{2}+1$$ has only prime of the form of (4k+1) , where n! has prime of the form( 4k-1) and (4k+1) .(adsbygoogle = window.adsbygoogle || []).push({});

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Square of x , added to one is not equal to n!

Tags:

Loading...

Similar Threads - Square added equal | Date |
---|---|

B Simple Question About Term(s) re: Fermat | Jan 19, 2018 |

B Calculating the area of a circle or square using decimals | Nov 9, 2017 |

B Square root of a negative number in a complex field | Oct 16, 2017 |

A Product of 3rd rank tensor with squared vector | Oct 11, 2017 |

B Adding fractions | Jul 20, 2016 |

**Physics Forums - The Fusion of Science and Community**