Standard Deviation: Formula (8) Approximation Explained

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To calculate the standard deviation of a function V(x1, x2, x3, x4) with standard normal variables and small variances, formula (8) serves as an approximation. The discussion emphasizes expressing the deviation in terms of partial derivatives and individual variable deviations. A Taylor expansion may be necessary to compute the standard deviation, and the relationship between "difference" and "variance" is explored. The conversation also clarifies that deviations (dx) can be treated as multiples of standard deviations. Overall, the thread highlights the mathematical approach to approximating standard deviation in this context.
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Hi all.

If I have a function V(x1,x2,x3,x4) and I want to calculate it's standard deviation when x1,x2,x3,x4 are standard normal and their variances are small, then formula (8) on this page
http://www.devicelink.com/mem/archive/99/09/003.html" is an approximation to the standard deviation. Can anyone offer me a proof or tell me where I can read more about this formula?

-Anders
 
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Hi.

Hmm, I think it's the clever part I don't understand then. Must I taylor expand V and then compute the standard deviation? And also, I can't see the connection between "difference" and "variance". I'd appreciate a few formulas. Thanks.

-Anders
 
I thought it would follow from dV = Sum[(partial V/partial xi) dxi, i=1,2,3,4]. The "d" operator is similar to "deviation" (e.g., from the mean). Let's say you have only 2 x's. Then dv = (Dv/Dx1) dx1 + (Dv/Dx2) dx2 ==> dv^2 = (Dv/Dx1)^2 dx1^2 + (Dv/Dx2)^2 dx2^2 + ignored term* approx. equal to (Dv/Dx1)^2 dx1^2 + (Dv/Dx2)^2 dx2^2. (I've used capital D for "partial.")

In fact, you don't even need the link I posted.

*This is the interaction term 2(Dv/Dx1)(Dv/Dx2) dx1 dx2. If you think that for a given "random draw" either of dx1 or dx2 (but not necessarily both, and you don't know which) is likely to be "very small" then you can assume 2(Dv/Dx1)(Dv/Dx2) dx1 dx2 = 0.
 
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Okay. The only part I don't understand now is why dx is the same as a standard deviation ?
 

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