MHB Standard deviation, Normal Distributions and Taking Random Samples

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To find the standard score (z-score) for the data value of 9 from a normal distribution with a mean of 16.8 and a standard deviation of 2.3, the formula used is z = (x - μ) / σ. Substituting the values, z = (9 - 16.8) / 2.3. This calculation results in a z-score of approximately -3.35. The discussion emphasizes the importance of showing progress when asking for help to facilitate better assistance. Understanding how to apply the z-score formula is crucial for analyzing data within normal distributions.
DarcyDorian
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Find the standard score for a the data value 9 from a normal distribution which has a
mean of 16.8 and a standard deviation of 2.3
 
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Hello and welcome to MHB, DarcyDorian! :D

We ask that our users show their progress (work thus far or thoughts on how to begin) when posting questions. This way our helpers can see where you are stuck or may be going astray and will be able to post the best help possible without potentially making a suggestion which you have already tried, which would waste your time and that of the helper.

Assuming you don't know how to begin, we will need the following formula:

[box=green]
The Normal Distribution

$z$-score for an $x$-value: $$z=\frac{x-\mu}{\sigma}$$[/box]

Now, we are given $x=9$, $\mu=16.8$ and $\sigma=2.3$, so can you use the above formula to compute $z$ (the standard score)? :)
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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