Stat/Thermo Problem - Equilibrium Pressure in Permeable Sphere

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SUMMARY

The equilibrium pressure in a permeable sphere filled with air and placed in a helium gas chamber is determined to be 2 atm. This conclusion is reached by applying the ideal gas law and considering the volume ratios of the sphere and chamber. The initial pressures of both gases are 1 atm, and the calculations involve the number of particles of air and helium, leading to the final pressure being double the initial pressure. The discussion emphasizes the validity of using entropy maximization as an alternative approach, although the ideal gas law provides a straightforward solution.

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  • Understanding of the Ideal Gas Law (P=NRT/V)
  • Knowledge of entropy concepts (S=ln(Q))
  • Familiarity with the properties of noble gases
  • Basic principles of thermodynamics and equilibrium
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  • Learn about entropy maximization techniques in thermodynamic systems
  • Explore the behavior of noble gases in various conditions
  • Investigate the implications of chemical reactions on equilibrium states
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Homework Statement



A sphere full of air at room temp and 1 atm is placed in a chamber filled with He gas at room temp and 1 atm. The sphere is permeable to He only. What will the equilibrium pressure in the sphere be?



Homework Equations



Variables:
Po=initial pressure
V=vol of sphere
V'=vol of chamber
Na=number of air particles
Nh=number of He particles

Ideal gas law: P=NRT/V

---------
I think that's all i need, but other eqs that might be relevant:

S=ln(Q) : entropy=ln(number of states)
dS/dE=1/T : derivative of entropy wrt Energy = 1/temp

The Attempt at a Solution



Here's what I think:

since He is a noble gas, we can assume it does not interact with the air particles. Therefore, at equilibrium, a single He molecule is equally likely to be found anywhere in the chamber (V'), which means that the mean number of He particles in the sphere (V) will be V/V'*Nh.

Then use the ideal gas law:
P=(V/V'*Nh+Na)RT/V

can also solve for Nh and Na initially in terms of Po, R, T and V or V':

Nh=PoV'/(RT), Na=PoV/(RT)

and then plug in, rearrange and reduce:

P=(Po/(RT))(V/V'*V'/V+V/V)*RT=Po(1+1)=2Po=2 atm

So, is there anything wrong with what I did? I don't know what the answer should be, but I'm not confident in my answer because my prof mentioned that we should start by maximizing entropy... which I could do, but this way seemed so much simpler. Suggestions? Any errors in my assumptions or approach? I don't find this material intuitive, so I could very well have made mistakes.

Thanks!
 
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Your approach is somewhat limited because it can't easily accommodate complications such as a chemical reaction (for example). As long as you can also apply the entropy maximization approach, though, I don't see a problem. In fact, I think it's great that you're attacking problems from different angles.
 

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