Stuck on Elevator Weight - Analyzing the Readings

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SUMMARY

The discussion focuses on the physics of weight measurement in an elevator scenario. When the elevator slows down, the scale registers a value less than 600 N due to the deceleration. When the elevator is stopped, the scale reads exactly 600 N, reflecting the gravitational force acting on the person. As the elevator accelerates downward, the scale shows a value less than 600 N again, indicating that the apparent weight decreases during downward acceleration. A free body diagram illustrates the forces acting on the person, including gravitational force and normal force from the scale.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of forces and weight measurement
  • Familiarity with free body diagrams
  • Concept of acceleration and deceleration
NEXT STEPS
  • Study Newton's second law of motion in detail
  • Learn how to draw and interpret free body diagrams
  • Explore the effects of acceleration on weight perception
  • Investigate real-world applications of weight measurement in elevators
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of weight measurement in dynamic environments.

hatingphysics
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:confused: I am having trouble answering this question...what is the answer?! HELP


Suppose you are in an elevator that is moving upward with a constant velocity. A scale inside the elevator shows your weight to be 600 N. (a) Does the scale register a value that is greater than, less than, or equal to 600 N during the time when the elevator slows down as it comes to a stop? (b) What is the reading when the elevator is stopped? (c) How does the value registered on the scale compare to 600 N during the time when the elevator picks up speed again on its way back down? Give your reasoning in each case.
 
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Draw a free body diagram. What forces are acting on the person?
 

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