Summation with binomial coefficients question

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Homework Help Overview

The discussion revolves around a summation involving binomial coefficients, specifically focusing on the expression \(\sum\limits_{r=0}^n\frac{1}{^nC_r}\) and a related double summation. Participants are exploring the implications of their derived equations and the relationships between variables.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to manipulate their derived equations to find a specific sum but questions the validity of their approach after encountering unexpected results. Some participants raise concerns about inconsistencies in variable substitutions, particularly regarding the use of \(m\) and \(n\). Others inquire about the evaluation of a related summation involving \(r\) and suggest focusing on individual terms within the double sum.

Discussion Status

The discussion is ongoing, with participants providing insights and questioning the assumptions made in the original equations. There is an exploration of different interpretations of the problem, and some guidance is offered regarding the approach to summing terms.

Contextual Notes

Participants are navigating potential inconsistencies in their equations and the implications of variable substitutions. The original poster has not yet reached a solution and is seeking clarification on their reasoning.

AdityaDev
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Homework Statement


##\sum\limits_{r=0}^n\frac{1}{^nC_r}=a##. Then find the value of $$\sum\sum\limits_{0\le i<j\le n}(\frac{i}{^nC_i}+\frac{j}{^nC_j})$$

Homework Equations



I have used two equations which I derived myself. This is the first one.
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The second one is:
20150430_000435-1.jpg


3. The Attempt at a Solution

Using first equation and second equation:
20150430_001236-1.jpg

Now I have to subtract the cases where I=j to get the required sum. But Iis the above conclusion correct? Because I am not getting the required answer after subtracting.
 

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In the last line of the derivation of your second equation, you have been inconsistent in your substitutions of m for n. Two m's should be m+1.
But I don't understand how you use this equation anyway. a is a function of n, but where you use the equation you seem to be using it as a generic fact for any m, without changing a. I.e. you cannot now substitute n for m as being equal.
 
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Then how do you find ##(2n+1)\sum\limits_{r=0}^n\frac{r}{^nC_r}##?
 
AdityaDev said:
Then how do you find ##(2n+1)\sum\limits_{r=0}^n\frac{r}{^nC_r}##?
I haven't solved it myself, yet.
You could try concentrating on one of the two terms in the double sum. You should be able to sum that over the 'other' variable.
 

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