Surface Area of Shoe Box Shape to Maximize Volume

Click For Summary
SUMMARY

The discussion focuses on maximizing the volume of a shoe box shape created from a rectangular piece of cardboard measuring 3 feet by 4 feet. By cutting squares of side length x from each corner, the dimensions of the box become L = 4 - 2x, W = 3 - 2x, and the height is x. The surface area formula used is 2ab + 2bc + 2ac, which is essential for calculating the outside surface area of the box. The goal is to determine the optimal value of x that maximizes the volume while adhering to the constraints of the cardboard dimensions.

PREREQUISITES
  • Understanding of basic geometry and volume calculations
  • Familiarity with algebraic expressions and equations
  • Knowledge of optimization techniques in calculus
  • Ability to manipulate equations to express dimensions in terms of a variable
NEXT STEPS
  • Learn about optimization techniques using calculus, specifically the first and second derivative tests
  • Study the concept of surface area and volume relationships in geometric shapes
  • Explore the method of Lagrange multipliers for constrained optimization problems
  • Practice problems involving maximizing volume with given surface area constraints
USEFUL FOR

Students studying geometry, mathematics educators, and anyone interested in optimization problems related to real-world applications such as packaging design.

JuliusDarius
Messages
25
Reaction score
0

Homework Statement


Imagine you have a rectangular piece of cardboard measuring 3 feet by 4 feet. You know that if you cut a square out of each corner, you can fold the pieces together and tape them together to make an object that looks like a shoe box:http://www.omahamathtutor.com/wp-content/uploads/2012/03/shoebox.png
What is the outside surface area of this shoe box shape that maximize the volume?



Homework Equations


2ab + 2bc + 2ac


The Attempt at a Solution


Not sure where to start
 
Physics news on Phys.org
V = L*W*H

Then express the length, width, and height in terms of x after you remove those four squares from the 4 x [STRIKE]12[/STRIKE] 3 rectangle.
 
Last edited:
Bohrok said:
V = L*W*H

Then express the length, width, and height in terms of x after you remove those four squares from the 4x12 rectangle.

Could you show me how to do that?
 
The length is originally 4, then you cut off two segments of length x from both ends of that side, so L = 4 - 2x. Same thing for the width.

After cutting out the four squares, you have four flaps that fold up; what would be the height of these flaps?
 

Similar threads

Replies
4
Views
12K
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
18
Views
8K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
2
Views
2K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 10 ·
Replies
10
Views
3K
Replies
24
Views
15K
  • · Replies 2 ·
Replies
2
Views
5K