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- Thread starter plmokn2
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rotational invariance of the Hamiltonian.

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Avodyne

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I think his 'momentum' here is angular momentum.

If your elliptically symmetric potential is [tex]V(\rho,z)=\frac{1}{\rho^2+\alpha z^2},~\alpha\neq 1[/tex], then angular momentum along axis

'z' is conserved.

If your elliptically symmetric potential is [tex]V(\rho,z)=\frac{1}{\rho^2+\alpha z^2},~\alpha\neq 1[/tex], then angular momentum along axis

'z' is conserved.

Last edited:

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malawi_glenn

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Thanks for your replies, sorry for the slightly ambiguious question.

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blechman

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