MHB T 4–4 Deposits needed to accumulate a future sum

  • Thread starter Thread starter karush
  • Start date Start date
  • Tags Tags
    Future Sum
Click For Summary
To accumulate $8,000 in 5 years with annual deposits at a 7% interest rate, the formula for future value with regular deposits is applied. The difference equation for the account balance is established, leading to a closed-form solution for the amount after n years. The final formula for the annual deposit, D, is derived as D = (A_n * i) / ((1 + i)^n - 1). By substituting the values, one can calculate the required annual deposit. This approach effectively determines the necessary contributions to reach the savings goal.
karush
Gold Member
MHB
Messages
3,240
Reaction score
5
T 4–4 Deposits needed to accumulate a future sum Judi wishes to accumulate \$8,000 by the end of 5 years by making equal annual end-of-year deposits over the next 5 years. If Judi can earn 7% on her investments, how much must she deposit at the end of each year to meet this goal?

$$\displaystyle A=P\left(1+\frac{r}{n}\right)^{nt}$$

ok not sure how plug this in

this complicated by the deposit made at the end of each year
 
Last edited:
Mathematics news on Phys.org
Let's let $D$ be the amount of the end of year deposits, and $i$ be the annual interest rate. So, the amount of the account at the end of year $n$ can be given by the difference equation:

$$A_n-(1+i)A_{n-1}=D$$ where $n\in\mathbb{N}$

The homogeneous solution is given by:

$$h_n=k_1(1+i)^n$$

And the particular solution is:

$$p_n=k_2$$

Plugging this into our difference equation, we find:

$$k_2-(1+i)k_2=D\implies k_2=-\frac{D}{i}$$

And so the closed form for $A_n$ is given by:

$$A_n=k_1(1+i)^n-\frac{D}{i}$$

Since:

$$A_1=D$$

We find:

$$k_1=\frac{D}{i}$$

And so the closed-form for $A_n$ is

$$A_n=\frac{D}{i}\left((1+i)^n-1\right)$$

Solve for $D$:

$$D=\frac{A_ni}{(1+i)^n-1}$$
 
good grief,,😎
 
I have been insisting to my statistics students that for probabilities, the rule is the number of significant figures is the number of digits past the leading zeros or leading nines. For example to give 4 significant figures for a probability: 0.000001234 and 0.99999991234 are the correct number of decimal places. That way the complementary probability can also be given to the same significant figures ( 0.999998766 and 0.00000008766 respectively). More generally if you have a value that...

Similar threads

Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
1
Views
7K
  • · Replies 2 ·
Replies
2
Views
7K
Replies
1
Views
2K
  • · Replies 27 ·
Replies
27
Views
4K
Replies
10
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K