MHB Tan (Theta - Pie) Answer Explained

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Tan(theta - pi) equals tan(theta) due to the periodic nature of the tangent function, which has a period of pi radians. This means that tan(theta + pi) and tan(theta - pi) both simplify to tan(theta). The discussion clarifies that the use of "pie" was a misunderstanding, as "pi" is the correct term in this mathematical context. The tangent function's properties confirm that the initial assertion about the value being tan(theta) is accurate. Thus, the answer to Tan(theta - pi) is indeed tan(theta).
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What does Tan (Theta - Pie) = ?

I know Tan (theta + pie) = tan (theta).

They say the answer is tan (theta), but I think it's some kind of typo.
 
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captainnumber36 said:
What does Tan (Theta - Pie) = ?

I know Tan (theta + pie) = tan (theta).

They say the answer is tan (theta), but I think it's some kind of typo.

Pie is a dessert, while pi is a Greek letter used to represent the ratio of a circle's circumference to its diameter. Having said that, the period of the tangent function is $\pi$ radians, which means:

$$\tan(\theta+\pi k)=\tan(\theta)$$ where $k\in\mathbb{Z}$ (this means $k$ can be any integer, even negative ones)

So, it's not a typo, your book is correct.
 
captainnumber36 said:
What does Tan (Theta - Pie) = ?

I know Tan (theta + pie) = tan (theta).

They say the answer is tan (theta), but I think it's some kind of typo.

sum/difference identity for tangent ...

$\tan(a \pm b) = \dfrac{\tan{a} \pm \tan{b}}{1 \mp \tan{a} \cdot \tan{b}}$

now, let $a = \theta$ and $b = \pi$ ... substitute & evaluate
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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