Terminal Velocity: Solving for D

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SUMMARY

The discussion centers on calculating the drag coefficient (D) required for a man weighing 50.0 kg to achieve a terminal velocity of 42 m/s. The user applied the formula V = (mg/D)^(1/2) and derived D = 0.28 kg/m. However, the textbook states the answer is 44 kg/m, leading to confusion about the correctness of the user's calculation versus the book's answer. The user's calculation is confirmed to satisfy the equation, indicating a potential error in the textbook.

PREREQUISITES
  • Understanding of terminal velocity concepts
  • Familiarity with drag force equations
  • Basic knowledge of physics, particularly Newton's laws
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Review the derivation of terminal velocity equations in physics
  • Study the factors affecting drag coefficients in fluid dynamics
  • Examine common errors in physics textbooks regarding terminal velocity
  • Explore practical applications of terminal velocity in real-world scenarios
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Physics students, educators, and anyone interested in understanding the principles of motion and forces, particularly in the context of terminal velocity calculations.

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Homework Statement



A man 50.0kg has a terminal velocity of 42m/s. What value of D is required to make this possible?

Homework Equations



V(terminal velocity) = (mg/D)^1/2

The Attempt at a Solution



D = (50kg*9.8m/s^2)/(42m/s)^2) = 0.28kg/m

The book's answer is 44kg/m. Is the book wrong or am I wrong?
 
Physics news on Phys.org
0.28 kg/m satisfies that equation.
 
NascentOxygen said:
0.28 kg/m satisfies that equation.

Thanks, I needed some reinforcement.
 

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