Terminal velocity with Reynods# and Drag Coeff.

Click For Summary
SUMMARY

The discussion revolves around calculating the terminal velocity of a smooth wooden ball using the terminal velocity equation and Reynolds number. The user provided specific parameters: the density of the ball (420 kg/m³), the density of air (1.1614 kg/m³), the dynamic viscosity (1.846 x 10^-5 N-s/m²), and the diameter of the ball (0.2 m). The user attempted to use the equation mg = (0.5)(rho_ball)(v²)(A)(drag_coeff) but encountered discrepancies between calculated Reynolds numbers and those in a provided table. The discussion highlights the need for correct density and area values in the terminal velocity equation.

PREREQUISITES
  • Understanding of terminal velocity equations
  • Knowledge of Reynolds number calculation
  • Familiarity with drag coefficients
  • Basic principles of fluid dynamics
NEXT STEPS
  • Review the correct application of the terminal velocity equation
  • Study the relationship between Reynolds number and drag coefficient
  • Learn how to determine the cross-sectional area of a sphere
  • Investigate the impact of fluid properties on drag forces
USEFUL FOR

Students studying fluid dynamics, physics enthusiasts, and anyone involved in calculating terminal velocity and drag forces in fluid environments.

joe3
Messages
1
Reaction score
0
Hi guys I've been reading on the boards for a few days now and everyone here seems really helpful, so I've decided to come and ask for some guidence on a problem I've been having



Homework Statement



I have to find the terminal velocity of a smooth wooden ball.
rho(ball)=420 kg/m^3
rho(air)=1.1614kg/m^3
mu=1.846x10^-5 N-s/m^2
dia(ball)=.2m

Homework Equations



I am given a table of about 25 reynolds numbers and drag coeff values, i can post them if it is necessary


The Attempt at a Solution



My approach was to use the terminal velocity equation

mg=(.5)(rho of ball)(v)^2(A)(drag coeff)

to guess a value for the velocity, then calculate the drag coeff, then use my guessed velocity to calculate reynolds number using

Re=[(rho ball)(v)(dia ball)]/mu

Then my plan was to take my calculated reynolds number(which i hoped was the same as one of the reynolds numbers in my given table) and then take the corresponding drag coeff and see if it matched my calulated drag coeff, and if it i would know that the guess i made for the terminal velocity was correct. But i cannot get this approach to work, my calulated Re values are much larger than my table values. Any suggestions?
 
Physics news on Phys.org
joe3 said:
Hi guys I've been reading on the boards for a few days now and everyone here seems really helpful, so I've decided to come and ask for some guidence on a problem I've been having



Homework Statement



I have to find the terminal velocity of a smooth wooden ball.
rho(ball)=420 kg/m^3
rho(air)=1.1614kg/m^3
mu=1.846x10^-5 N-s/m^2
dia(ball)=.2m

Homework Equations



I am given a table of about 25 reynolds numbers and drag coeff values, i can post them if it is necessary


The Attempt at a Solution



My approach was to use the terminal velocity equation

mg=(.5)(rho of ball)(v)^2(A)(drag coeff)

to guess a value for the velocity, then calculate the drag coeff, then use my guessed velocity to calculate reynolds number using

Re=[(rho ball)(v)(dia ball)]/mu

Then my plan was to take my calculated reynolds number(which i hoped was the same as one of the reynolds numbers in my given table) and then take the corresponding drag coeff and see if it matched my calulated drag coeff, and if it i would know that the guess i made for the terminal velocity was correct. But i cannot get this approach to work, my calulated Re values are much larger than my table values. Any suggestions?
Your terminal velocity equation is incorrect. What densiy (and what area) should you be using?
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
1K
Replies
10
Views
2K
  • · Replies 13 ·
Replies
13
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
13
Views
3K
  • · Replies 6 ·
Replies
6
Views
8K
  • · Replies 165 ·
6
Replies
165
Views
8K