- #1

Rijad Hadzic

- 321

- 20

## Homework Statement

The Lunar Reconnaissance Orbiter (LRO) with mass m= 1850, maps the surface of the moon from an orbital altitude of 50 km. what are the magnitude and direction of the force the LRO experiences due to the moons gravity?

## Homework Equations

Fg = (GMm)/r^2

## The Attempt at a Solution

First I started by changing the units to SI

Mass of moon M = .07x10^24 kg

Mass of orbiter m = 1850 kg

Gravitational constant = 6.637 x 10^-11

the radius = (radius of moon + orbital altitude ) = 1.738 x 10^6 (value from my book) + 50,000 =

1788000

Now I just use the formula: [itex] F_g = (6.637x10^{-11})(.07x10^24)(1850) / 1788000^2 = 2688.478434 N [/itex]

but my books answer is 2.83 x 10^3 N

I don't understand what I did wrong as my answer comes from the formula... is there some trick I am missing??