The force LRO experiences due to moons gravity?

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Homework Help Overview

The problem involves calculating the gravitational force experienced by the Lunar Reconnaissance Orbiter (LRO) due to the moon's gravity while in orbit at a specified altitude. The subject area pertains to gravitational forces and orbital mechanics.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the gravitational force formula, converting units and calculating the radius from the moon's surface to the orbiter's altitude. They express confusion regarding a discrepancy between their calculated result and the book's answer, questioning the accuracy of the mass provided for the moon.

Discussion Status

Participants have engaged in clarifying the method used by the original poster, with some suggesting that the mass of the moon may not be precise enough for accurate results. The discussion reflects a mix of validation of the approach and exploration of the implications of significant figures on the outcome.

Contextual Notes

There is mention of significant figures in the context of the mass of the moon, which may affect the accuracy of the calculated gravitational force. The original poster's concern about the book's mass value suggests potential constraints in the provided information.

Rijad Hadzic
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Homework Statement


The Lunar Reconnaissance Orbiter (LRO) with mass m= 1850, maps the surface of the moon from an orbital altitude of 50 km. what are the magnitude and direction of the force the LRO experiences due to the moons gravity?

Homework Equations


Fg = (GMm)/r^2

The Attempt at a Solution


First I started by changing the units to SI
Mass of moon M = .07x10^24 kg
Mass of orbiter m = 1850 kg
Gravitational constant = 6.637 x 10^-11

the radius = (radius of moon + orbital altitude ) = 1.738 x 10^6 (value from my book) + 50,000 =
1788000

Now I just use the formula: F_g = (6.637x10^{-11})(.07x10^24)(1850) / 1788000^2 = 2688.478434 N

but my books answer is 2.83 x 10^3 N

I don't understand what I did wrong as my answer comes from the formula... is there some trick I am missing??
 
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You used the mass of Moon with one significant figure. Why do you expect your result to be accurate to more than that?
 
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Likes   Reactions: Buzz Bloom
I see what you mean. Does the method I am using right though?

Sucks that my book would give me mass that would give an inaccurate answer..
 
The method is fine.
With a more precise mass for the Moon the answer will get closer to the book's answer.
 

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