The fragmentation function of ##K^{*0}## particle?

  • Context: Graduate 
  • Thread starter Thread starter Chenkb
  • Start date Start date
  • Tags Tags
    Function Particle
Click For Summary
SUMMARY

The fragmentation function (FF) of the ##K^{*0}(892)## particle is not available in the online FF generator at http://lapth.cnrs.fr/ffgenerator/. Users have confirmed that the ##K^{*0}##, being a resonance, does not have a fragmentation function but decays isotropically according to standard matrix elements. The discussion clarifies that the inquiry pertains to the quark fragmentation into hadrons, specifically the function ##D^{q\to h}## where ##h = K^{*0}(892)## and ##q = u,d,s,c,\cdots##.

PREREQUISITES
  • Understanding of particle physics and resonances
  • Familiarity with fragmentation functions in quantum chromodynamics (QCD)
  • Knowledge of matrix elements and isotropic decay processes
  • Experience with online FF generators and their limitations
NEXT STEPS
  • Research the properties of resonances in particle physics
  • Explore fragmentation functions for other hadrons using the online FF generator
  • Study the mathematical formulation of matrix elements in decay processes
  • Investigate the role of quark flavors in hadronization
USEFUL FOR

Particle physicists, researchers in quantum chromodynamics, and students studying hadronization processes will benefit from this discussion.

Chenkb
Messages
38
Reaction score
1
Where can I find the fragmentation function (FF) of ##K^{*0}(892)## particle?
The online FF generator doesn't give the option of ##K^{*0}##

FF generator: http://lapth.cnrs.fr/ffgenerator/
 
Physics news on Phys.org
Are you sure that the K* has a fragmentation function? I'm pretty sure that, since it is a resonance, it doesn't fragment but simply decay isotropically according to the usual matrix elements. What are you looking for it?
 
Einj said:
Are you sure that the K* has a fragmentation function? I'm pretty sure that, since it is a resonance, it doesn't fragment but simply decay isotropically according to the usual matrix elements. What are you looking for it?
Oops, sorry for my ambiguity. Actually I mean the quarks fragment into hadrons, i.e. the fragmentation function is ##D^{q\to h}## with ##h = K^{*0}(892)##, and ##q = u,d,s,c,\cdots##.
For ##h = pion, kaon...##, it is available(given by online FF generator), but what about ##K^{*0}##?
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K