The laws of motion - rock sliding on a roof

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Homework Help Overview

The problem involves a rock sliding up a sloped roof at an angle of 37.0°, with an initial speed and a coefficient of kinetic friction. The task is to determine the maximum height the rock reaches after sliding up the incline and before entering free fall.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the equations of motion and energy conservation, questioning the kinetic energy of the rock at maximum height and the effects of friction. Some suggest using work-energy concepts for analysis.

Discussion Status

The discussion includes various interpretations of the problem, with participants questioning assumptions about energy conversion and the behavior of the rock at its highest point. Some guidance has been offered regarding the application of energy principles.

Contextual Notes

There are mentions of potential confusion regarding angle measurement and the implications of kinetic energy at maximum height. Participants are exploring these concepts without reaching a definitive conclusion.

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The laws of motion -- rock sliding on a roof

Homework Statement



One side if the roof of a house slopes up at 37.0°.A roofer kicks a round,flat rock that has been thrown onto the roof by a neighborhood child.The rock slides straight up the incline with an initial speed of 15ms-1.The coefficient of kinetic friction between the rock and the roof is 0.400.The rock slides 10.0m up the rock and the roof crosses the ridge and goes into free fall, following a parabolic trajectory above the far side of the roof,with negligible air resistance.Determine the maximum height the rock reaches above the point where it was kicked.

Homework Equations


The Attempt at a Solution


Are there anything wrong?
Let the maximum height the rock reaches above the point where it was kicked be h.
1/2mv2=mgh+fs
1/2m(15)2=9.8mh+0.4xmx9.8xcos37°x10
 
Last edited:
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What is the acceleration the rock will undergo while sliding up the roof ? From this calculate the velocity of the rock just before it leaves the roof. What do you get ?

Edit :You can also approach this problem using Work Energy concepts .
 
Last edited:
Angles are not measured in degrees Celsius.
 
haha1234 said:
Let the maximum height the rock reaches above the point where it was kicked be h.
1/2mv2=mgh+fs
1/2m(15)2=9.8mh+0.4xmx9.8xcos37x10
That looks right to me.
 
haha1234 said:
Are there anything wrong?
Let the maximum height the rock reaches above the point where it was kicked be h.
1/2mv2=mgh+fs

Does the rock have any kinetic energy when it reaches maximum height?
 
TSny said:
Does the rock have any kinetic energy when it reaches maximum height?
Do I still get to keep my award for the year?:redface:
 
haruspex said:
Do I still get to keep my award for the year?:redface:

:smile: (Definitely!)
 
TSny said:
Does the rock have any kinetic energy when it reaches maximum height?

I think...no.
This is because all the energy will convert to potential energy.
 
haha1234 said:
I think...no.
This is because all the energy will convert to potential energy.

What would happen to the rock (which is traveling along a parabolic arc) if it came to rest at its highest point?
 

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  • #10
TSny said:
What would happen to the rock (which is traveling along a parabolic arc) if it came to rest at its highest point?

Thanks!I can find the correct answer now!
 
Last edited:
  • #11
SteamKing said:
Angles are not measured in degrees Celsius.
:smile:
 

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