The length of time of the refrigerator

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SUMMARY

The discussion revolves around calculating the operational time required for a refrigerator with a Coefficient of Performance (COP) of 2.8 to cool 12 kg of water from 40°C to 10°C. The refrigerator consumes 400W of electric power during operation. To determine the cooling time, one must apply thermodynamic principles and energy equations, specifically focusing on the heat removal required and the efficiency of the refrigerator.

PREREQUISITES
  • Understanding of thermodynamics principles, specifically heat transfer.
  • Familiarity with the Coefficient of Performance (COP) in refrigeration.
  • Basic knowledge of energy consumption calculations.
  • Ability to perform calculations involving mass, specific heat capacity, and temperature change.
NEXT STEPS
  • Research the formula for calculating heat transfer: Q = mcΔT.
  • Learn about the implications of Coefficient of Performance (COP) in refrigeration systems.
  • Explore energy consumption calculations for electrical appliances.
  • Investigate the efficiency of well-insulated containers in thermal management.
USEFUL FOR

Students in thermodynamics, engineers working with refrigeration systems, and anyone interested in energy efficiency calculations for cooling applications.

oliverjames
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A refrigerator with an average COP of 2.8 is used to cool a well-insulated container whose contents are equivalent to 12 Kg of water from 40 degree C to 10 degree C. When running, the refrigerator consumes 400W of electric power. The length of time the refrigerator must run to accomplish this cooling is
can anyone help me to solve this.
thanks
james


 
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welcome to pf!

hi james! welcome to pf! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:

(same with your other questions, of course)
 

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