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- Letting the original triangle of the iteration that results in the Koch snowflake =s: Taking the limit of the Koch snowflake perimeter as s goes to zero intuitively would be infinity, although at s=0 the perimeter would be zero. I'm not sure how that works as an iterated limit.

On one side, if I have any finite value of s = the side of the original triangle of the Koch snowflake iteration, then the perimeter is infinite, so intuitively

On the other hand, if I looked at the end result first and considered how it got there, then intuitively

(Obviously

These are the intuitive answers, but intuition is a lousy guide, so I am not sure how this works out as an iterated limit.

Thanks for any pointers.

(Note: this is not a homework question or part of any course, so if the problem is not well posed, I am the clumsy one.)

On the other hand, if I looked at the end result first and considered how it got there, then intuitively

(Obviously

*n=infinity and s=0, the perimeter is zero, but I am wondering about the limits)***at**These are the intuitive answers, but intuition is a lousy guide, so I am not sure how this works out as an iterated limit.

Thanks for any pointers.

(Note: this is not a homework question or part of any course, so if the problem is not well posed, I am the clumsy one.)