The ONLY solution of PDE: f_t g_r = f_r g_t ?

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SUMMARY

The only solution to the partial differential equation (PDE) defined by the relationship \( f_t g_r = f_r g_t \) is \( f = h(g) \), where \( h \) is an arbitrary function. This conclusion is supported by the Maple PDE solver, which confirms that this form encompasses all possible solutions. To establish that \( f = h(g) \) is the sole solution, one must demonstrate that any deviation from this form leads to contradictions in the PDE structure.

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The ONLY solution of PDE: f_t g_r = f_r g_t ?

I have the following PDE:

\frac{\partial f(r,t)}{\partial t} \, \, \frac{\partial g(r,t)}{\partial r} = \frac{\partial f(r,t)}{\partial r} \, \, \frac{\partial g(r,t)}{\partial t}

By a simple check, I know a solution is f = h(g), where h() is arbitrary function. The Maple PDE solver returns exactly that.

How can I prove, f=h(g) is the ONLY type of solution of that PDE?
 
Last edited:
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Your statement is equivalent to

\frac{\partial (f,g)}{\partial (t,\tau)} = 0
 


Thanks!
 

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