The units digit of a triangular number iw ## 0, 1, 3, 5, 6 ##?

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SUMMARY

The units digit of a triangular number, defined as \( t_{n} = \frac{n^{2}+n}{2} \) for \( n \geq 1 \), can be conclusively determined to be one of the following digits: 0, 1, 3, 5, 6, or 8. This conclusion is derived by evaluating \( n \) modulo 10, which results in the units digits of triangular numbers being \( t_{n} \equiv 0, 1, 3, 6, 10, 15, 21, 28, 36, \) or \( 45 \) modulo 10. The proof confirms that these digits are the only possible outcomes for the units digit of triangular numbers.

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Homework Statement
Prove the following statement:
The units digit of a triangular number is ## 0, 1, 3, 5, 6 ##, or ## 8 ##.
Relevant Equations
None.
Proof:

Let ## t_{n} ## denote the ## nth ## triangular number such that ## t_{n}=\frac{n^{2}+n}{2} ## for ## n\geq 1 ##.
Then ## n\equiv 0, 1, 2, 3, 4, 5, 6, 7, 8 ##, or ## 9\pmod {10} ##.
Thus ## t_{n}\equiv 0, 1, 3, 6, 10, 15, 21, 28, 36 ##, or ## 45\pmod {10} ##.
Therefore, the units digit of a triangular number is ## 0, 1, 3, 5, 6 ##, or ## 8 ##.
 
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Math100 said:
Homework Statement:: Prove the following statement:
The units digit of a triangular number is ## 0, 1, 3, 5, 6 ##, or ## 8 ##.
Relevant Equations:: None.

Proof:

Let ## t_{n} ## denote the ## nth ## triangular number such that ## t_{n}=\frac{n^{2}+n}{2} ## for ## n\geq 1 ##.
Then ## n\equiv 0, 1, 2, 3, 4, 5, 6, 7, 8 ##, or ## 9\pmod {10} ##.
Thus ## t_{n}\equiv 0, 1, 3, 6, 10, 15, 21, 28, 36 ##, or ## 45\pmod {10} ##.
Therefore, the units digit of a triangular number is ## 0, 1, 3, 5, 6 ##, or ## 8 ##.
Right. I think it is time to proceed to the next paragraph now, something more challenging.
 
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