Thermal Energy problem - Ice placed in water

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SUMMARY

The problem involves calculating the mass of an ice cube placed in 240g of water at 21.5 degrees Celsius, reaching a final equilibrium temperature of 15 degrees Celsius. The relevant equation is mCΔt = -mCΔt, where m represents mass, C is specific heat capacity, and Δt is the change in temperature. The heat capacity of ice does not need to be considered until it melts, as the temperature of the ice remains constant at its freezing point until complete melting occurs. The latent heat of fusion of ice and the specific heat capacity of water are crucial for solving this problem.

PREREQUISITES
  • Understanding of the latent heat of fusion of ice
  • Knowledge of specific heat capacity of water
  • Basic algebra for solving equations
  • Familiarity with thermal equilibrium concepts
NEXT STEPS
  • Research the latent heat of fusion of ice (334 J/g)
  • Learn about specific heat capacity of water (4.18 J/g°C)
  • Practice solving thermal energy problems using mCΔt equations
  • Explore the concept of thermal equilibrium in closed systems
USEFUL FOR

High school students studying thermodynamics, physics educators, and anyone interested in understanding heat transfer and phase changes in materials.

Bobazoide
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Homework Statement


An ice cube at its freezing point is placed in nested Styrofoam cups which contain 240g of water at 21.5 degrees C. If the final equilibrium temperature when the last trace of ice melts is 15 degrees C, what was the mass of the ice cube?


Homework Equations


mCΔt = -mCΔt

The Attempt at a Solution


My problem here is the logistics of the question itself. As the ice melts, it turns into water, which has a different heat capacity than that of ice. I'm not sure if I have to take this constantly changing heat capacity into account, since I'm only in grade 11 of high school and my class hasn't been taught complex mathematics, so our teacher expects us to solve this with basic arithmetic. I'm not sure if he wants us to just use a constant specific heat capacity or not, but logically it would have to change.
 
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Bobazoide said:

Homework Statement


An ice cube at its freezing point is placed in nested Styrofoam cups which contain 240g of water at 21.5 degrees C. If the final equilibrium temperature when the last trace of ice melts is 15 degrees C, what was the mass of the ice cube?


Homework Equations


mCΔt = -mCΔt That line has no sense.

The Attempt at a Solution


My problem here is the logistics of the question itself. As the ice melts, it turns into water, which has a different heat capacity than that of ice. I'm not sure if I have to take this constantly changing heat capacity into account, since I'm only in grade 11 of high school and my class hasn't been taught complex mathematics, so our teacher expects us to solve this with basic arithmetic. I'm not sure if he wants us to just use a constant specific heat capacity or not, but logically it would have to change.

The ice cube is placed into the water at its freezing point. The temperature of ice will not change until it melts, so you do not need to calculate with the heat capacity of the ice. You need to know the latent heat of fusion of ice, and the specific heat capacity of water.

What is the equation you need to use?

ehild
 

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