Thiosulfate Standardization via Iodate Titration

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SUMMARY

The discussion focuses on calculating the concentration of Thiosulfate using Iodate titration. Given a 0.00167M Iodate solution and 0.71266g of Thiosulfate, the calculated concentration of Thiosulfate is 0.1406M. However, the density of the Thiosulfate solution is 1.0163 g/mL, which indicates that the initial assumption of 1g=1mL leads to a 1.6% error in the final result. Accurate density values must be considered for precise calculations.

PREREQUISITES
  • Understanding of molarity and its calculations
  • Familiarity with titration techniques and stoichiometry
  • Knowledge of molecular weights (MW) of Iodate and Thiosulfate
  • Basic principles of solution density and its impact on concentration calculations
NEXT STEPS
  • Study the principles of titration and how to perform it accurately
  • Learn about calculating molarity and adjusting for solution density
  • Explore the implications of stoichiometric ratios in chemical reactions
  • Research the properties and applications of Thiosulfate in analytical chemistry
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Chemistry students, laboratory technicians, and professionals involved in analytical chemistry and titration methods will benefit from this discussion.

belyzel4
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Homework Statement


How do I figure out the concentration of Thiosulfate in mol/L or g/L if I am only given the following:

0.00167M Iodate (IO3-)
10g of 0.00167M Iodate (IO3-) in Solution
0.71266g of Thiosulfate necessary to titrate
IO3- MW = 174.9027 g/mol
Thiosulfate MW = 248.18 g/mol

Homework Equations


Molarity = moles/L
IO3- + 8I- + 6H+ -----> 3I3- + 3H2O
I3- + 2S2O3 -----> 3I- + S4O6

The Attempt at a Solution


Using 1g~1mL
0.00167M IO3- * (0.01 L) * (3 mol I3 / 1 mol IO3) * (2 mol S2O3 / 1 mol I3) * (1 / 0.71266 mL) * (1000 mL / 1 L) = 0.1406M S2O32-
 
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With the assumption 1g=1mL your result is correct.

But: the density of 0.1406M sodium thiosulfate is not 1 g/mL, but 1.0163 g/mL. I am not convinced you are expected to use this number, but it definitely shows your final result is wrong by about 1.6%.
 

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