This answer has been edited to fix the grammar and punctuation errors.

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aaaa202 said:

I have tried to plug A and the expression for ln(t)> into 6.3 a) on page 96 but end up with a double integral after doing the linear approximation of the time evolution operator. Is my method correct


Yes, you have the correct approach. But I think you should be careful with the notation and use a carat ^ to denote any operator or state in the interaction picture (as introduced in section 5.3 of the notes.) Also, there is no operator ##\hat{H}''## with a double prime.

You only want to keep terms up to first order in ##\hat{H}'##. So, you should not get a double integral. You will have two single integrals that you can combine into one single integral.

how do I conjugate transpose the expression for U when given by the first order integral?

It should be easy to take the Hermitian conjugate of ##\hat{U}## since ##\hat{H}'(t)## is a Hermitian operator.

Second of all I am quite confused by the notation <A>_0. Does that simply mean <A(t0)> or am I missing something?

See just below equation (6.6). The notation ##\langle \rangle_0## means an equilibrium average with respect to the Hamiltonian ##H_0##. Thus ##\langle A \rangle_0## means exactly the expression defined by equation (6.1a). Note that ##\langle A \rangle_0## is time independent, so you don't need to worry about the time for this quantity.
 

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