- #1

flyingpig

- 2,580

- 1

## Homework Statement

Let's say I have [tex]V = P\frac{a}{b+a}[/tex]

Solve for a

So I did the math and I got [tex]\frac{Vb}{V+P}[/tex]

Then I decided to do it again and tried to invert both sides of [tex]V = P\frac{a}{b+a}[/tex] to [tex]V^-1 = P^-1(\frac{a}{b+a})^-1[/tex]

Now my question is, why isn't [tex](\frac{a}{b+a})^-1[/tex] = [tex]\frac{b+a}{a}[/tex]