Three blocks connected by two strings: tensions?

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Homework Help Overview

The problem involves three blocks connected by strings on a frictionless surface, with a force applied to the last block. Participants are tasked with finding the tensions in the strings connecting the blocks.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to estimate the tensions based on proportional reasoning but expresses uncertainty about their guesses. Other participants discuss the acceleration of the system and the forces acting on each block, suggesting a systematic approach to find the tensions.

Discussion Status

Some participants have provided feedback on the original poster's reasoning, clarifying the relationship between the applied force and the tensions in the strings. There is a productive exchange of ideas regarding the acceleration of the blocks and the forces involved, but no explicit consensus has been reached.

Contextual Notes

The original poster appears to be unsure about the relevant equations and concepts, which may affect their understanding of the problem. The discussion includes assumptions about the system being frictionless and the uniform acceleration of the blocks.

ddtozone
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Homework Statement



Three blocks on a frictionless surface are connected by strings like so (from left to right):
Block 1 (m=10kg) to string with Tension 1 to Block 2 (m=20kg) to string with Tension 2 to Block 3 (m=30kg) to string with Tension 3.
The blocks are pulled to the right with force T3=60N.
Find T1 and T2.

Homework Equations



I'm not even sure... maybe
Fn=mg


The Attempt at a Solution



I would guess T1 is 20N and T2 is 40N, because it's proportional to T3. But this doesn't seem correct. Could I please get some feedback?


Thank you!
 
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T3 accelerates 3 blocks, T2 accelerates 2 blocks, etc.
 
if i am not wrong,

consider the entire system of 3 blocks

force to the right 60N = mass of 3 blocks (60kg) x acceleration

'a' is the same for the entire system. so , 'a' is the same for each block

so your acceleration is = 60/60 = 1

so for tension 1, which pulls only block 1, to have a = 1, it must have a force acting on it by f=ma = (10kg)(1) = 10N, so tension is = 10N

for tension 2, which pulls block 1 and block 2, a = 1, f=ma = (10+20)(1) = 30N

for tension 3, which pulls block 1,2,3, a = 1, f= ma = (10+20+30)(1) = 60N
 
Thanks a ton! That makes much more sense.
 

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