Time-evolution of a quantum system

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SUMMARY

The discussion focuses on the time evolution of an electron bound in a hydrogen atom under a homogeneous magnetic field, represented by the Hamiltonian H = H0 - ωLz. The initial state of the system is given as |ψ(t=0) = 1/√2 (|2,1,-1> - |2,1,1>). Participants explore the calculation of probabilities for various states |ψ1(t), |ψ2(t), and |ψ3(t) using the time evolution operator U(t) = exp(-iHt/ħ). The conversation highlights the necessity of transforming the wavefunction into matrix form and emphasizes the importance of ensuring that the probabilities sum to one.

PREREQUISITES
  • Quantum mechanics fundamentals, specifically the concept of wavefunctions and Hamiltonians.
  • Understanding of time evolution operators in quantum systems, particularly U(t) = exp(-iHt/ħ).
  • Familiarity with matrix representations of quantum states and operators.
  • Knowledge of calculating probabilities from quantum states and ensuring normalization.
NEXT STEPS
  • Study the derivation and application of the time evolution operator in quantum mechanics.
  • Learn about the normalization condition for quantum states and how to ensure probabilities sum to one.
  • Explore the matrix representation of angular momentum operators, particularly Lz.
  • Investigate the implications of magnetic fields on quantum systems, focusing on Zeeman effect and perturbation theory.
USEFUL FOR

Students and professionals in quantum mechanics, physicists working with atomic systems, and anyone interested in the mathematical modeling of quantum states under external fields.

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Homework Statement


Consider an electron bound in a hydrogen atom under the influence of a homogenous
magnetic field B = zˆB  . Ignore the electron spin. The Hamiltonian of the system is H = H0 −ωLz ,where
H0 is the Hamiltonian of the hydrogen atom with the usual eigenstates nlm and eigenenergies (0) En
(we use the superscript (0) to denote the unperturbed hydrogen atom), and ω =|e |B/(2mec).

At t = 0 the system is in the state: |ψ(t=0)>=1/\sqrt{2}((|2,1,-1> -|2,1,1>)
For each of the following states
calculate the probability of finding the system at some later time t > 0 in that state:

1(t)>=1/\sqrt{2}(|2,1,-1&gt; - |2,1,1&gt;)<br /> <br /> |ψ<sub>2</sub>(t)&gt;=1/\sqrt{2}(|2,1,-1&amp;gt; + |2,1,1&amp;gt;)&lt;br /&gt; &lt;br /&gt; |ψ&lt;sub&gt;3&lt;/sub&gt;(t)&amp;gt;=1/\sqrt{2}(|2,1,0&amp;amp;gt;&amp;lt;br /&amp;gt; &amp;lt;br /&amp;gt; &amp;lt;h2&amp;gt;Homework Equations&amp;lt;/h2&amp;gt;&amp;lt;br /&amp;gt; &amp;lt;br /&amp;gt; |ψ(t)&amp;amp;gt;=U(t)*|ψ(t=0)&amp;amp;gt;&amp;lt;br /&amp;gt; U(t)=exp(-i*H*t/\hbar)&amp;lt;br /&amp;gt; &amp;lt;br /&amp;gt; &amp;lt;h2&amp;gt;The Attempt at a Solution&amp;lt;/h2&amp;gt;&amp;lt;br /&amp;gt; &amp;lt;br /&amp;gt; So the time evolution of a system can be described by multiplying the wavefunction at t=0 by the function U(t) which in this case would be exp(-i*(E&amp;lt;sub&amp;gt;n&amp;lt;/sub&amp;gt;&amp;lt;sup&amp;gt;(o)&amp;lt;/sup&amp;gt;-|e |B/(2m&amp;lt;sub&amp;gt;e&amp;lt;/sub&amp;gt;c)*t/\hbar). But then from there, I&amp;amp;#039;m a bit confused. Do I need to transform the equation into a matrix form and then take the square of the coefficients of the superimposed wavefunctions to get the probabilities? If that was the case, then I&amp;amp;#039;d be able to represent |ψ&amp;lt;sub&amp;gt;1&amp;lt;/sub&amp;gt;(t)&amp;amp;gt;=1/\sqrt{2}[-1,0,1], |ψ&amp;lt;sub&amp;gt;2&amp;lt;/sub&amp;gt;(t)&amp;amp;gt;=1/\sqrt{2}[1,0,1] and then |ψ&amp;lt;sub&amp;gt;3&amp;lt;/sub&amp;gt;(t)&amp;amp;gt;=[0,1,0] right? &amp;lt;br /&amp;gt; &amp;lt;br /&amp;gt; Thanks for your help.
 
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Ok, so I tried the matrix approach, but it doesn't seem quite right. Here is what I did:

With U(t)=exp(-i*(En(o)-|e |B/(2mec)*t/\hbar) I split that up into
U(t)=exp(-i*En(o)t/hbar)*exp(i*α*t/\hbar) where α=|e|B/(2mec)

from there I used the equation exp(iθ\widehat{n}\bullet\vec{σ})=Icos(θ)+i\widehat{n}\bullet\vec{σ}sin(θ)

where 'I' is the identity matrix

which gave me Icos(αt)+iBLzsin(αt) where I used the matrix representation of Lz

Now multiplying this new expression for U(t) gives me
|ψ(t)>=exp(i*En(o)*(cos(αt)|ψ1> -i*B*hbar*sin(αt)|ψ2>)

And we can take the square of the coefficients of the wavefunctions as their probabilities. So for example, the probability of |ψ3> would be 0, because it doesn't appear in the equation. Now, apart from appear really tenuous, the squares of the probabilities don't add up to 1, which makes me really doubt this is correct. Maybe I'd need to integrate from t=0 --> infinity, but that's a rather hard integral, and not likely either. Am I at least close?
 

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