Time for an echo to return in a 1.50 km canyon at 245 Hz

[Brittykitty]

A 245 Hz sound with a wavelength of 1.41 m is projected into a narrow canyon. If the canyon is 1.50 km long, what time does it take an echo to be heard?

How would I solve for this question? :)

 

[rock.freak667]

Given the frequency and wavelength, what is the speed of your wave?

 

[Brittykitty]

245[hz] * 1.41[m] = 345 m/s? :)

 

[rock.freak667]

245[hz] * 1.41[m] = 345 m/s? :)

Right, so the wave must travel 1.5 km while traveling at 345 m/s, how would you find the time taken given the distance traveled and the speed?

 

[Brittykitty]

t=d/s
t=1.5km/ 345ms?
t=4.35s?

 

[rock.freak667]

Yes that should be it.

 

[Brittykitty]

Thank you SO much! :D