Titriation Calculation for Weak Acid, Strong Base

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SUMMARY

This discussion focuses on the titration calculation of 50.0 mL of 1.00 M acetic acid with 1.00 M sodium hydroxide. The initial pH is determined using the formula pH = -log([H+]), where [H+] is derived from the dissociation of acetic acid. The acid dissociation constant (Ka) for acetic acid is 1.75 x 10-5, which is essential for calculating the concentrations in the ICE table. Participants emphasize the importance of using the pKa value and provide resources for verifying pH calculations.

PREREQUISITES
  • Understanding of weak acid dissociation and the ICE table method
  • Familiarity with acid dissociation constants (Ka) and their significance
  • Knowledge of pH calculations and logarithmic functions
  • Basic principles of acid-base titration
NEXT STEPS
  • Research how to construct and interpret titration curves for weak acids
  • Learn to use the Henderson-Hasselbalch equation for buffer solutions
  • Explore the use of pH calculators for titration scenarios
  • Study the impact of different concentrations of titrants on titration curves
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Chemistry students, educators, and anyone involved in analytical chemistry or laboratory work focusing on acid-base titrations.

linuxux
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Homework Statement



Sketch curve of pH vs volume of base added for the titration of 50.0ml of 1.00M acetic acid with 1.00M sodium hydroxide.

Homework Equations



none, i think.

The Attempt at a Solution



Okay, first off, this is a weak acid, the first point on the curve would be the initial [H+] in the solution, so pH=-log([H+]). But i thought weak acids have very few H+ ions, almost none, thus the initial [H+]=0, but there is no exponent (other than infinity) that will give you zero, so this must be a situation where you use an ICE table to find [H+], but i was given no Ka value! so how can i solve for "x" in the ICE table? Can someone show me exactly how to find the important points so i can sketch the graph. thanks.

p.s. the pKa value of acetic acid was given in a previous question, i wonder if i am allowed to use it in this problem? I am really stuck here...
 
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Linuxux,
You need to understand that a weak acid, such as acetic, will dissociate in water, so the dissociation for this acid will be significant. Now about not being given the Ka value for acetic acid, just look in a table of acid dissociation constants. An analytical chemistry textbook here gives a Ka of 1.75*10^(-5). Now, simply make use of the expression and equation for Ka. Keep in mind the amounts of base titrant that you add.

To start with, having no base yet added, you use something like:

Ka = (H)*(Ac)/(HAc), in which the items in parentheses are the molar concentrations, using H for hydronium, Ac for acetate anion, HAc for acetic acid.
 
thanks for help.
 
i got my answer here:
http://www.brynmawr.edu/Acads/Chem/Chem104lc/study/buffer6.html

check your answer by comparing you pH/pOH value with the case that applies to you here, http://www.ausetute.com.au/titrcurv.html
 
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