Torque & Force Homework Solution

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SUMMARY

The discussion focuses on solving a physics problem involving a wrecking ball supported by a boom and a tension cable. The weight of the wrecking ball is 4800 N, and the boom weighs 3600 N. The tension in the support cable is calculated to be 12455 N, while the force exerted by the hinge at point P is determined to be 10562 N horizontally and 875 N vertically. The equations used include torque and force balance equations, specifically ΣT = 0, ΣFx = 0, and ΣFy = 0.

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Homework Statement



A wrecking ball (weight = 4800 N) is supported by a boom, which may be assumed to be uniform and has a weight of 3600 N. A support cable runs from the top of the boom to the tractor. The angle between the support cable and the horizontal is 32, and the angle between the boom and the horizontal is 48. Find (a) the tension in the support cable and (b) the magnitude of the force exerted on the lower end of the boom by hinge at point P.


Homework Equations


\SigmaT = Fr = 0
\SigmaFx = -Tcos\Theta + Rx = 0
\SigmaFy = -Wball - Wboom +Tsin\Theta+Ry = 0

The Attempt at a Solution


\SigmaT = 3600 (L/2) + 4800 L - Ft sin32 L = 0
\SigmaT = 1800 L + 4800 L = Ftsin32L
\SigmaT = 6600 = Ft sin 32
Ft = 12455N

Fx = -Ftcos32 + Rx = 0
Fx = -12455 cos 32= -Rx
Rx = 10562 N

Fy = -4800 - 3600sin48 + Ftsin 32 + Ry = 0
Fy = -4800 -3600sin48 + 12455sin 32 +Ry = 0
Ry = 875N
 
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My physics teacher gave us a set of bonus problems over break and I cannot figure this one out. I got an answer but I do not think it is right. If anyone knows how to do this, could you please help me out. Thank you very much
 

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