Total or kinetic energy in Bethe Bloch stopping power?

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SUMMARY

The discussion centers on the interpretation of energy in the Bethe-Bloch and Bethe-Heitler formulas, specifically whether the energy \(E\) refers to total relativistic energy or kinetic energy. The consensus is that \(E\) represents total energy, \(E = K + mc^2\), as this is more general. The confusion arises regarding the particle's mass during energy loss in materials, with clarification that the rest mass remains constant while the kinetic energy decreases. The Bethe-Heitler formula is noted to be a valid approximation only when \(E \gg mc^2\).

PREREQUISITES
  • Understanding of the Bethe-Bloch formula for ionization energy loss
  • Familiarity with the Bethe-Heitler formula for Bremmstrahlung energy loss
  • Knowledge of relativistic energy concepts, including total energy and kinetic energy
  • Basic principles of particle interactions in materials
NEXT STEPS
  • Study the derivation and applications of the Bethe-Bloch formula in particle physics
  • Explore the conditions under which the Bethe-Heitler formula is applicable
  • Investigate the relationship between kinetic energy and total energy in relativistic contexts
  • Learn about calorimetry and its methods for measuring particle energy
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Physicists, particularly those specializing in particle physics and radiation interactions, as well as students seeking to understand energy loss mechanisms in materials.

crick
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The average loss of energy in a material per unit length of a particle (in particular an electron, which is stable) is described by the quantity ##dE/dx##.

- for ionization it is given by the Bethe-Bloch formula $$-\left\langle {\frac {dE}{dx}}\right\rangle ={\frac {4\pi }{m_{e}c^{2}}}\cdot {\frac {nz^{2}}{\beta ^{2}}}\cdot \left({\frac {e^{2}}{4\pi \varepsilon _{0}}}\right)^{2}\cdot \left[\ln \left({\frac {2m_{e}c^{2}\beta ^{2}}{I\cdot (1-\beta ^{2})}}\right)-\beta ^{2}\right]$$
- for Bremmstralungh it is given by the Bethe-Heilter formula $${\displaystyle -\left\langle {\frac {dE}{dx}}\right\rangle \approx {\frac {4N_{a}Z^{2}\alpha ^{3}(\hbar c)^{2}}{m_{e}^{2}c^{4}}}E\ln {\frac {183}{Z^{1/3}}}}$$

I can't understand if the "energy ##E##" in the formulas is the total relativistic energy or the kinetic energy ##K## only?

In the first case ##E=K +mc^2##, while in the second case ##E=K##.

It looks like that the first case is the right one, since it's more general, but in that case I cannot understand how the particle, stopping in the material for various processes can change its mass (the electrons are stable so they do not decay after they have stopped). Does this really happen or does it loose before all its kinetic energy and then its rest energy?

I'm confused also because I read that in calorimeters the range of the particle is used to measure its energy: does this energy include the rest energy?
 
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For the left side it does not matter as both only differ by a constant which doesn't change the derivative.
The Bethe-Heitler formula is only a good approximation for ##E\gg mc^2## which means it doesn't matter either.
 
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mfb said:
For the left side it does not matter as both only differ by a constant which doesn't change the derivative.
The Bethe-Heitler formula is only a good approximation for ##E\gg mc^2## which means it doesn't matter either.

Thank you for the answer! By "differing by a constant" in the left side are you referring to the fact that the rest mass ##mc^2## is constant?
 
It's simpler than that. df/dx = dg/dx is f(x) = g(x) + a constant.
 
Last edited:
crick said:
Thank you for the answer! By "differing by a constant" in the left side are you referring to the fact that the rest mass ##mc^2## is constant?
Right. The derivative of the total energy and the derivative of the kinetic energy are the same.
 

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