- #1

Plutonium88

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now i found how to do the solution by doing an "Unorthodox" method of completing the square, could some one explain why the guy called it unorthodox?

Solution:

x^4 + 4

x^4 + 4 +4x^2 -4x^2 (completing the square)

(x^2 + 4x^2 + 4) - (2x)^2

(x^2 + 2)^2 - (2x)^2

(x^2 +2 - 2x)(X^2 + 2 + 2x)

Ans: (x^2 +2x - 2)(x^2 +2x +2)Now initially i didn't get this question on my tests. So I'm curious, how would i have known or how can i change my way of thinking so that i could use this technique, because i still don't exactly get it completely.

In completing the square i remember

ax^2 + bx + c

so now you take(b/2)^2 = a number

you rewrite your formula

ax^2 + BX + C -(B/2)^2 + (b/2)^2and then factor... in this question though, you have no b term... so yea can some one just point me in the direction i need to be thinking?

Solution:

x^4 + 4

x^4 + 4 +4x^2 -4x^2 (completing the square)

(x^2 + 4x^2 + 4) - (2x)^2

(x^2 + 2)^2 - (2x)^2

(x^2 +2 - 2x)(X^2 + 2 + 2x)

Ans: (x^2 +2x - 2)(x^2 +2x +2)Now initially i didn't get this question on my tests. So I'm curious, how would i have known or how can i change my way of thinking so that i could use this technique, because i still don't exactly get it completely.

In completing the square i remember

ax^2 + bx + c

so now you take(b/2)^2 = a number

you rewrite your formula

ax^2 + BX + C -(B/2)^2 + (b/2)^2and then factor... in this question though, you have no b term... so yea can some one just point me in the direction i need to be thinking?

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