Trig Quadrant Question: Solving for secx=-5.2, 0≤x≤2π

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Solve: secx=-5.2, 0≤x≤2π

I'm getting 2 answers:
1.76, 4.52

The answer key is telling me there is only one
1.76

How do I only get 1 answer from this?

Thanks,
 
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Evaluate: cot4.47

I'm getting .23 when i plug in: tan(1/4.47)

but the answer key says .25
am I doing something wrong?

thanks
 
1. [tex]\sec x = -5.2, \; 0\leq x\leq 2\pi[/tex]

[tex]\frac{1}{\cos x} = - 5.2[/tex]

[tex]\cos x = -\frac{1}{5.2} =[/tex]

[tex]\arccos(\cos x) = 1.76[/tex]

[tex]x = 1.76[/tex]2. [tex]\cot 4.47 = \frac{1}{\tan 4.47}[/tex] not [tex]\tan(\frac{1}{4.47})[/tex]
 
thanks, I see what I did wrong for #2

but, why doesn't #1 have 2 answers?
 
Because the second answer is in quadrant 4, where cos is positive.
 
No, it's in the 3rd quadrant. There should be 2 solutions.
 
Alright
Thanks everyone