Two stones dropped at the same time. Quick question, .

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Homework Help Overview

The problem involves two identical stones being dropped from a tall building at different times, with the assumption that air resistance is negligible. The inquiry focuses on the behavior of the vertical distance between the stones as they fall under the influence of gravity.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the effects of gravity on both stones, questioning whether the distance between them remains constant or changes over time. There is an exploration of the implications of one stone being dropped after the other and how that affects their relative motion.

Discussion Status

Some participants have provided clarifications regarding the timing of the drops and the resulting acceleration of the stones. There is an acknowledgment of the initial confusion, but explanations have helped some participants gain a better understanding of the situation.

Contextual Notes

There is a reference to a textbook answer indicating that the distance between the stones will increase, which raises questions about the assumptions of equal acceleration despite the staggered release times.

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Homework Statement


Two identical stones are dropped from a tall building, one after the other. Assume air resistance is negligible. While both stones are falling, what will happen to the vertical distance between them?


Homework Equations



a) It will increase.

b) It will first increase and then remain constant.

c) It will remain the same.

d) It will decrease.




The Attempt at a Solution



Assuming air resistance in negligible, wouldn't the stones both be affected equally and fall to the ground at the same rate of gravitational pull? They would both fall at the rate of 9.81m/s^2 and thus the distance between them would remain the same? Or would it increase until both were falling at this rate and then remain equal?

The book says that the answer is "It will increase" but that would mean that two things being affected by the same force have different accelerations? Why is this?
 
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The key phrase is 'one after the other'. They are not dropped at the same time.
 
wolfmanzak said:
Assuming air resistance in negligible, wouldn't the stones both be affected equally and fall to the ground at the same rate of gravitational pull?
The would experience the same acceleration, yes.
wolfmanzak said:
They would both fall at the rate of 9.81m/s^2
Correct.
wolfmanzak said:
and thus the distance between them would remain the same?
No.
wolfmanzak said:
Or would it increase until both were falling at this rate and then remain equal?
No.

Suppose the first stone was released at t=0 from a height of h=h_0. Its height is then governed by

h_1 = h_0 -\frac{g}{2}t^2

Yes? Suppose the second stone is released from the same height at t=t_0>0. The its height is

h_2 = h_0 - \frac{g}{2}(t-t_0)^2\;\;\;\text{for}\;\;\;t>t_0.

The difference in height is then

h_2-h_1 = -\frac{g}{2}(t-t_0)^2 + \frac{g}{2}t^2

which obviously increases with time (you can plot it to convince yourself).

More intuitively, since the first stone starts accelerating before the second stone and both accelerate at the same rate, the first stone is always traveling faster than the second.

Does that make sense?

Edit: I see Doc beat me to it :frown:
 
I think I understand the concept now. It makes a little more sense after these explanations. Thank you both.
 

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