Two's Complement: 8-bit Arithmetic - 8710 - 2910

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Discussion Overview

The discussion revolves around performing an arithmetic operation using 8-bit two's complement representation, specifically the subtraction of 29 from 87. Participants are focused on the conversion of decimal numbers to their binary two's complement forms.

Discussion Character

  • Homework-related

Main Points Raised

  • One participant presents the arithmetic operation and seeks confirmation on the correctness of their binary conversions for the numbers 87 and 29.
  • Another participant confirms the conversion of 29 to its two's complement binary form.
  • A later post points out a discrepancy in the initial post regarding the number 89 being mentioned instead of 87.

Areas of Agreement / Disagreement

Participants generally agree on the conversion of 29 to its two's complement representation, but there is a noted discrepancy regarding the use of the number 89 instead of 87, indicating some confusion that remains unresolved.

Contextual Notes

The discussion does not clarify the implications of the discrepancy between the numbers mentioned, nor does it resolve the arithmetic operation itself.

naspek
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Homework Statement


Perform the following arithmetic operation using 8-bit
two's complement

a) 8710 - 2910


The Attempt at a Solution


i just want to know.. am i converting the number correctly?

89 = 0101 1001
-29 = 1110 0011
 
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Yep, you did that correctly.
 
thanks.. =)
 
naspek said:

Homework Statement


Perform the following arithmetic operation using 8-bit
two's complement

a) 8710 - 2910
One quibble: you wrote 87 above, but worked with 89 below.
naspek said:

The Attempt at a Solution


i just want to know.. am i converting the number correctly?

89 = 0101 1001
-29 = 1110 0011
 

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