UFO - time taken to travel to moon

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The discussion centers on calculating the time taken for a UFO to travel from Earth to the Moon, utilizing the time dilation formula Δt = γΔt0. An astronaut on the Moon observes the UFO 2 seconds after it was seen above Earth, leading to a calculated proper time (Δt0) of 1.6 seconds for the UFO's travel. The user initially miscalculated the time due to confusion between Δt and Δt0 but improved their answer to 1.547 seconds after clarification. The rounding discrepancy with the book's answer is acknowledged but deemed unimportant.

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A UFO is observed just above the surface of the Earth moving at a constant velocity. An astronaut on the moon (3.8 x 10^8 m from earth) observes the UFO just above the surface of the moon 2.0s later.

From the UFO's reference frame, how long did it travel from the Earth to the moon?

The answer is given as 1.6s




I was using equation;

Δt = γΔt0

With t0 = 2 seconds

the velocity in γ I calculated to be 1.9x10^8 by using
v=distance/time
v=(3.8x10^8)/2
v=1.9x10^8

But I'm getting an incorrect answer of 2.58 seconds.
 
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ZedCar said:
I was using equation;

Δt = γΔt0

With t0 = 2 seconds
You're mixing up Δt & Δt0.
 
Thanks Doc Al.

Now I'm getting an answer of 1.547 seconds which is a lot better.

I'm not sure why the book has rounded the answer up to 1.6s
 
ZedCar said:
I'm not sure why the book has rounded the answer up to 1.6s
Beats me. I wouldn't worry about it.

The main thing is to know how and when to apply the time dilation formula.
 
Thank you :smile:
 

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