Uncertainty in measurement (GRE question)

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SUMMARY

The discussion revolves around a GRE problem concerning the measurement of radioactive decay using the Poisson distribution. A student recorded ten one-second measurements of decay events, yielding values of 3, 0, 2, 1, 2, 4, 0, 1, 2, and 5, resulting in a standard deviation of 2.4. To achieve an uncertainty of 1 percent, the student must determine the appropriate counting time based on the relationship between standard deviation and average decay rate. The average decay rate from the measurements is calculated to be 2 decays per second.

PREREQUISITES
  • Understanding of the Poisson distribution
  • Knowledge of standard deviation calculations
  • Familiarity with radioactive decay concepts
  • Basic statistical analysis skills
NEXT STEPS
  • Research the application of the Poisson distribution in radioactive decay measurements
  • Learn how to calculate uncertainty in measurements
  • Study the relationship between standard deviation and average in statistical contexts
  • Explore advanced statistical methods for improving measurement accuracy
USEFUL FOR

Students preparing for the GRE, physicists working with radioactive materials, and anyone interested in statistical analysis of decay events.

0ddbio
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This is actually a GRE problem, I'm just trying to go through and understand them all for studying purposes, but I don't understand how to do this one at all.

Homework Statement


A student makes 10 one-second measurements of the disintegration of a sample of long-lived radioactive isotope and obtains the following values.
3, 0, 2, 1, 2, 4, 0, 1, 2, 5
How long should the student count to establish the rate to an uncertainty of 1 percent?

Homework Equations


I have no idea. But I would guess that standard deviation might be involved..
[tex]\sigma_{x}^{2}=\langle x^{2}\rangle-\langle x\rangle^{2}[/tex]

The Attempt at a Solution


But I am unsure how to get time involved in this. But the standard deviation is 2.4
Any help is appreciated.
 
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Here's the Wikipedia article on the Poisson distribution: http://en.wikipedia.org/wiki/Poisson_distribution

The Poisson distribution is the probability density function for the number of events that will occur during some interval if the average number of events that occur per interval is a known constant (it will not always be exactly the average because the process is random; the Poisson distribution is what describes the spread). For a radioactive isotope, an "event" is a decay. Obviously as the sample decays the expected number of decays per second decreases, but I think we are meant to ignore that since the isotope is "long-lived," and presumably the sample is very large. The Poisson distribution has the interesting property that the (ideal, not sample) standard deviation is the square root of the average,

The average of the ten numbers you listed is 2, so we can take that to be the average number of decays per second. If you take longer time intervals, the average and standard deviation both increase.

This problem is asking you to find the time required for the standard deviation divided by the average to reach 0.01.
 

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