$$x+y+xy=11\quad[1]$$
$$x^2+xy+y^2=19\quad[2]$$
$$\text{Note that }x=0,y=0\text{ and }x=y=0\text{ do not give solutions.}$$
$$[1]+[2]\Rightarrow(x+y)^2+(x+y)-30=0\Rightarrow(x+y-5)(x+y+6)=0$$
$$x+y=-6\Rightarrow xy=17\quad(\text{from }[1])$$
$$x+\frac{17}{x}=-6\Rightarrow x^2+6x+17=0\Rightarrow\text{ no solutions.}$$
$$x+y=5\Rightarrow xy=6\quad(\text{from }[1])$$
$$x+\frac6x=5\Rightarrow x^2-5x+6=0\Rightarrow x\in\{2,3\}$$
$$\text{As equations }[1]\text{ and }[2]\text{ are symmetrical, we have }(x,y)=(2,3),(3,2)\text{ as solutions.}$$