Understanding Analytic Functions and Convergence

  • Thread starter Thread starter JamesGoh
  • Start date Start date
  • Tags Tags
    Function
Click For Summary
An analytic function at a point x0 has a power series representation that converges within a radius R greater than 0, meaning for all x values, |x-x0| must be less than R. Convergence refers to the sequence of partial sums in a series approaching a limit. The truth value of whether a function is analytic at x0 does not depend on variable x, but solely on the function and the point x0. The inclusion of "absolutely" in the definition is debated, but in the context of complex functions, absolute convergence is equivalent to convergence. Overall, the key point is that a function must have a convergent series representation within a specified radius to be considered analytic.
JamesGoh
Messages
140
Reaction score
0
From my lecture notes I was given, the definiton of an analytic function was as follows:

A function f is analytic at xo if there exists a radius of convergence bigger than 0 such that f has a power series representation in x-xo which converges absolutely for [x-xo]<R

What I undestand is that for all x values, |x-xo| must be less than R (radius of convergence) in order for f to be analytic at xo.

Convergence in a general sense is when the sequence of partial sums in a series approaches a limit

Is my understanding of convergence and analytic functions correct ?
 
Physics news on Phys.org
JamesGoh said:
What I undestand is that for all x values, |x-xo| must be less than R (radius of convergence) in order for f to be analytic at xo.
What you're saying here would imply that the truth value ("true" or "false") of the statement "f is analytic at x0" depends on the value of some variable x. It certainly doesn't. It depends only on f and x0. (What you said is actually that if |x-x0|≥R, then f is not analytic at x0).

I'm a bit surprised that your definition says "converges absolutely". I don't think the word "absolutely" is supposed to be there. But then, in \mathbb C, a series is convergent if and only if it's absolutely convergent. So if you're talking about functions from \mathbb C into \mathbb C, then it makes no difference if the word "absolutely" is included or not.

What the definition is saying is that there needs to exist a real number R>0 such that for all x with |x-x0|<R, there's a series \sum_{n=0}^\infty a_n \left( x-x_0 \right)^n that's convergent and =f(x).

I like Wikipedia's definitions by the way. Link.
 

Similar threads

  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
26
Views
2K
Replies
7
Views
2K
Replies
23
Views
3K
  • · Replies 17 ·
Replies
17
Views
2K