Understanding Dissociation Energy: O2+ vs O2

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Dissociation energy varies between O2 and O2+ due to differences in bond order, which is calculated using the number of electrons in bonding and antibonding orbitals. For O2, the bond order is 2, while for O2+, it is 2.5, indicating a stronger bond in O2+. This higher bond order in O2+ results from the removal of an electron from an antibonding orbital, enhancing the stability of the bond. Understanding these concepts through molecular orbital theory is crucial for grasping the differences in dissociation energies. This highlights the importance of electron configuration in determining molecular stability.
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I am having some trouble understanding this concept. I get that the dissociation energy for N2 is much greater than N2+ because of the triple bond, which makes a stronger bond, and therefore it is harder to remove one bond, compared to N2+ where it is easier to remove the bond because of one less electron. My professor today though was saying that for oxygen, the dissociation energy of O2+ is higher than just O2. She explained why with orbital theory, but I was having trouble keeping up Can someone tell me why?

thanks
 
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bond order = (#electrons in bonding orbitals - #electrons in antibonding orbitals)/2

In N2, bond order is (8-2)/2 = 3
In N2+, it is (7-2)/2 = 2.5 (lower, weaker bond)

Your textbook should have MO pictures for N2, O2

Do a similar calculation for O2, you should see why O2+ has a higher bond order
 
thank you for your help
 

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