Understanding Inverse Trig Notations: Clarifying tan-1x and tan-2x

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Rose Garden
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I just want to know, what tan-1x means to you guys? does it mean arctan or cot?
What about tan-2x? Isn't that cot2x? Shouldn't the notation tan-2x be banned to avoid misinterpreting it as an inverse trig function?
 
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tan-1(x) means arctan to me. But it's a very unfortunate notation. That's why I always use arctan atan or bgtan instead of tan-1...
 
It's indeed an unfortunate notation. However, LaTeX language has the function [itex]\arctan[/itex] but I couldn'f find one for <arccotangent>, even though [itex]\cot[/itex] exists. Unfortunately, the very friendly Mathematica software uses the misleading notation.

http://www.wolframalpha.com/input/?i=Integrate+1/(1+x^2)+

And the inverse hyperbolic functions are not defined in LaTeX, apparently.
 
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Rose Garden said:
I just want to know, what tan-1x means to you guys? does it mean arctan or cot?
What about tan-2x? Isn't that cot2x? Shouldn't the notation tan-2x be banned to avoid misinterpreting it as an inverse trig function?

Hi Rose Garden. Yes I would interpret [itex]\tan^{-1}x[/itex] as arctan(x), while I would interpret [itex]\tan^{-2}x[/itex] as [itex]\cot^2x[/itex].

In most cases hopefully the context would make it clear what function one was using, but in general I'd say that you should interpret [itex]\tan^{n}x[/itex] as [itex](\tan \, x)^n[/itex] for all values of [itex]n[/itex] except [itex]n=-1[/itex] which should be treated as arctan (and similar applies to the other trig functions).

BTW. If ever you wish to use the "-1" notation to mean reciprocal with a trig function just use the bracketed notation as for example :

[tex]{\rm cosec} \, x = (\sin x)^{-1}[/tex]
 
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As is usually the case, context means a lot. When you're dealing with a variable, x-1 means the reciprocal of x, of 1/x.

When you're dealing with functions, however, an exponent of -1 usually means the inverse of the function. So tan-1(x) means arctan(x), not 1/tan(x).