Understanding Isotropic Decay: Solving Jackson's Problem

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I am trying to solve a problem from Jackson's and it says that the decay in particle's rest frame is more or less isotropic. I was wondering if somebody could help me figure the meaning of an 'isotropic decay' here.

Thank you in advance.
 
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Isotropic means all directions are equally likely.
 
hamster143 said:
Isotropic means all directions are equally likely.

I knew that sense of the term, but that meaning doesn't really help solving the this problem.
 
I think it should mean of the following:
1- the magnitude of spatial momenta is almost the same for all decay products,
2- the magnitude of temporal momenta (energy) is almost the same for all decay products.

But I can't figure out which description is actually meant just from the look of the problem.
 
The definition as I heard from the instructor is as follows:

A decay is isotropic if it is so in the Center of Mass frame; in the sense that the decay products come out in all angles with the same probability (but of course with fixed relative angles between them imposed by momentum conservation).