Understanding Relativistic Energy Equations: Are They Linear?

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SUMMARY

Einstein's relativistic energy equations are not linear with respect to velocity changes at relativistic speeds. The primary equation discussed is E = m0c2 / √(1 - v2 / c2), which illustrates how energy varies with velocity. Additionally, the alternative form E = √((m0c2)2 - (p c)2) is highlighted for its applicability to massless particles like photons. The relationship between energy and velocity is complex and does not follow a direct proportionality as velocity approaches the speed of light.

PREREQUISITES
  • Understanding of Einstein's theory of relativity
  • Familiarity with the concepts of rest mass (m0) and relativistic momentum (p)
  • Basic knowledge of algebra and square roots
  • Concept of the speed of light (c) as a constant
NEXT STEPS
  • Study the derivation of Einstein's energy-momentum relation
  • Explore the implications of relativistic speeds on mass and energy
  • Learn about the behavior of massless particles, particularly photons
  • Investigate applications of relativistic energy equations in modern physics
USEFUL FOR

Physicists, students of physics, and anyone interested in the principles of relativity and energy transformations at high velocities.

jaketodd
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Are Einstein's energy equations for relativistic speeds linear? For example, if you had something going at relativistic speed and then slowed it, but still had it at relativistic speed, would the decrease in energy be directly proportional to the amount you slowed the thing down?

Thanks,

Jake
 
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Relativistic energy:

E = \frac{m_0 c^2}{\sqrt{1 - v^2 / c^2}}

Work out an example or two for yourself, and see what you get.
 
You can also use:

E = \sqrt{(m_0 c^2)^2 - \frac{(m_0 v c)^2}{(1-v^2/c^2)}} = \sqrt{(m_0 c^2)^2 - (p c)^2}

Where p = relativistic momentum. This form has the advantage that it can be used for particles with zero rest mass like photons.
 

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