Understanding the Born Rule for Continuous Particle Position Measurement"

  • Context: Graduate 
  • Thread starter Thread starter nomadreid
  • Start date Start date
Click For Summary

Discussion Overview

The discussion revolves around the Born rule in quantum mechanics, specifically its application to continuous measurements of a particle's position over time. Participants explore the implications of the Born rule for calculating probabilities in continuous measurement scenarios and how this relates to the quantum Zeno effect.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant proposes that the probability of a continuous measurement for a particle's position being in the interval [a,b] at least once during the time interval [t1,t2] could be calculated using the integral ∫t1t2∫ab|ψ(x,t)|2dx dt, but questions whether this is correct.
  • Another participant mentions the quantum Zeno effect as a relevant concept in this context, suggesting a connection between continuous measurements and the effect.
  • A third participant provides links to reviews and discussions on continuous measurements and the quantum Zeno effect, indicating multiple perspectives on the topic.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the appropriate calculation for the probability in continuous measurements, and multiple viewpoints regarding the quantum Zeno effect are presented.

Contextual Notes

The discussion includes references to external resources that may provide additional insights but does not resolve the mathematical or conceptual uncertainties raised by participants.

nomadreid
Gold Member
Messages
1,773
Reaction score
256
If I have the formulation right, the Born rule says that the probability that a measurement for the position of the particle at time t will be in the real interval [a,b] equals ∫ab|ψ(x,t)|2dx. Fine. So, is the probability that a continuous measurement for the position of the particle will be in the real interval [a,b] at least once during the time interval [t1,t2] just equal to ∫t1t2ab|ψ(x,t)|2dx dt, or does this not work? If not, is there a more appropriate calculation?
 
Physics news on Phys.org
Thanks, bhobba and atyy. Never considered that! Fascinating...
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 96 ·
4
Replies
96
Views
9K
  • · Replies 13 ·
Replies
13
Views
6K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K