Understanding the Splitting of (1 to (n-1)) in Economics Lecture Notes

  • Thread starter Thread starter toni
  • Start date Start date
Click For Summary
SUMMARY

The discussion clarifies the mathematical concept of splitting the sum from 1 to (n-1) into the difference between the sum from 1 to infinity and the sum from n to infinity. Specifically, it confirms that both sums indeed contain (n-1) terms, as demonstrated with the example where n=5. The confusion arises from a miscount of terms, which is resolved by explicitly calculating the sums. The explanation effectively illustrates the relationship between these sums and reinforces the understanding of infinite series in economics.

PREREQUISITES
  • Understanding of basic summation notation
  • Familiarity with infinite series concepts
  • Knowledge of mathematical induction
  • Basic algebra skills
NEXT STEPS
  • Study the properties of infinite series in calculus
  • Learn about the convergence of series and their implications
  • Explore mathematical induction techniques for proving summation identities
  • Investigate applications of summation in economic models
USEFUL FOR

Students of economics, mathematicians, and educators looking to deepen their understanding of summation techniques and their applications in economic theory.

toni
Messages
19
Reaction score
0
I got this from my Economics lecture notes...

How come 1 to (n-1) can be split up into [(1 to infinity) minus (n to infinity)]?

What confuses me is the former one has (n-2) terms, but the latter one has only (n-1) terms...

And it doesn't make sense to me graphically...
 

Attachments

  • Picture 1.png
    Picture 1.png
    3.3 KB · Views: 468
Physics news on Phys.org
The thing that is confusing you is not true. Both sums have n-1 terms.

Did you try seeing what happens with specific n? If n= 5, the sum from 1 to n-1= 4 is [itex]a_1+ a_2+ a_3+ a_4[/itex]. That has 4= n-1 terms, not n-2.

The sum from 1 to infinity would be [itex]1+ a_1+ a_2+ a_3+ a_4+ a_ 5+ a_6+ a_7+ \cdot\cdot\cdot+[/itex] while the sum from n to inifinity is [itex]a_5+ a_6+ a_7+ \cdot\cdot\cdot[/itex]. Subtracting the second from the first leaves [itex]a_1+ a_2+ a_3+ a_4[/itex] as claimed.
 
I see! Thank you soooo much!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
  • · Replies 11 ·
Replies
11
Views
5K
Replies
2
Views
6K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
2
Views
3K