Understanding Vector Forces: 250 N at 50 Degrees

[motoxtremechick]

A worker lifts a sign by exerting a force along a rope of 250 N at an angle of 50 degrees with respect to the ground

i don't even know where to start...=\..just need a push in the right direction please

 

[Mindscrape]

Hah, that's not your problem statement...

 

[motoxtremechick]

ha o right..i guess that didnt even make sense
so I am sposed to draw a coordinate system and sketch the vector
would it just be a 50 degree angle? or what

 

[Mindscrape]

Yeah, basically the picture that makes the most sense to me is that this worker is standing right next to the sign, and pulls on some rope he has attached to himself and the sign with a force of 250N at the angle of 50 degrees.

Is that all, to draw the vector and the coordinate system? Probably ought to put the origin at the sign, for obvious reasons.

 

[motoxtremechick]

alright thanks so much! I am way struggling in this class just got my 5th concussion and have been missing class so nothings making sense at all
so thanks a bunch!

 

[Mindscrape]

Gross. No problem.

The resultant x and y vectors would be 250cos50, since cos50 = x/hypotenus (where the hyp is the force), and 250sin50 in case you were wondering about those.

 

[motoxtremechick]

Oh ok sweet thanks a lot! =]