Uniform Circular Motion - Finding Linear Speed

[MohammadG]

Homework Statement

The Bohr model of the hydrogem atom has one electron rotating around its center.
If it has a radius of 5.29 * 10^-11 m. And the mass of the electron is : 9.11 * 10^-31. And the electrostatic force between the orbiting electron and the center proton is 8.20 * 10^-8.

Find:
1) the centripetal acceleration of the electron
2) The linear speed of the electron
3) the period of the the electrons rotation

Homework Equations

t = 2 ∏ r / V

The Attempt at a Solution

Part 1 I managed to calculated. I got the correct answer of a_c = 9.00 * 10²².

I also found that Velocity is equal to 2182104.645 ms/s.

However for the period and the linear speed I am stuck.

For the period I get:
t = 2 ∏ r / V
t = 1.52321 * 10^-16

^according to the answer sheet this answer is wrong and should be, 4.82*10^-16

For the linear speed I am stuck. What exactly am I finding? I have no idea what to do.
^ the apparent answer is 6.9 x 10⁵

NOTE: Answers may be wrong as this textbook often has incorrect answers.

Thanks!

 

[tiny-tim]

Hi MohammadG!

Part 1 I managed to calculated. I got the correct answer of a_c = 9.00 * 10²².

I also found that Velocity is equal to 2182104.645 ms/s.
…
For the linear speed I am stuck. What exactly am I finding? I have no idea what to do.
^ the apparent answer is 6.9 x 10⁵

I suspect you've used the wrong numbers.

Did you use v= √(ra) ?