(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The Bohr model of the hydrogem atom has one electron rotating around its center.

If it has a radius of 5.29 * 10^{-11}m. And the mass of the electron is : 9.11 * 10^{-31}. And the electrostatic force between the orbiting electron and the center proton is 8.20 * 10^{-8}.

Find:

1) the centripetal acceleration of the electron

2) The linear speed of the electron

3) the period of the the electrons rotation

2. Relevant equations

t = 2 ∏ r / V

3. The attempt at a solution

Part 1 I managed to calculated. I got the correct answer of a_{c}= 9.00 * 10^{22}.

I also found that Velocity is equal to 2182104.645 ms/s.

However for the period and the linear speed im stuck.

For the period I get:

t = 2 ∏ r / V

t = 1.52321 * 10^{-16}

^according to the answer sheet this answer is wrong and should be, 4.82*10^{-16}

For the linear speed im stuck. What exactly am I finding? I have no idea what to do.

^ the apparent answer is 6.9 x 10^{5}

NOTE:Answers may be wrong as this textbook often has incorrect answers.

Thanks!

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# Homework Help: Uniform Circular Motion - Finding Linear Speed

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