Can somebody double check me on this.(adsbygoogle = window.adsbygoogle || []).push({});

At 5 p.m., Alex rode off from Asteroid. One hour later, Jessica rode off from Asteroid in the opposite direction at a speed 400 kph less than that of Alex. If they were 7900 km apart at 11 p.m., how fast did each travel

Answer in the form: Alex, Jessica

Alex rode off at 5 p.m. at x km

By 11 p.m. (6 hours later), his distance was 6x km

Jessica rode off at 6 p.m. at x-400 km

By 11 p.m. (5 hours later), her distance was: 5(x-400) km

The total distance between them was 7900 km.

6x + 5(x-400)=7900

6 x 900 = 5400 (Alex)

900 - 400= 500 x 5 = 2500 (Jessica)

5400+2500 = 7900

So Alex's speed was 900 and Jessica's was 500

Answered in form 900, 500

Did i do this correctly? I Know i've posted this problem before but it was in the wrong section. And i solved it the correct way this time i hope...

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# Uniform Motion Problems Part.2

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