What should I be thinking about to solve Uniform Motion Problems?

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Homework Help Overview

The discussion revolves around a uniform motion problem involving a helicopter and a car, where the helicopter overtakes the car after the latter has a head start. Participants are exploring the setup and reasoning required to solve the problem, which involves understanding the relationship between rate, time, and distance.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the initial attempts to set up equations based on the rates of the helicopter and car, with some confusion about how to incorporate the head start time of the car. Questions about the appropriate equations for uniform motion are raised, particularly regarding the relevance of acceleration terms.

Discussion Status

There is an ongoing exploration of the problem, with some participants providing hints and suggestions for approaching the solution. However, there is no explicit consensus on the best method to set up the equations, and multiple interpretations of the problem's requirements are being considered.

Contextual Notes

Participants note that the problem may be more suited for an introductory physics forum rather than a precalculus mathematics context, indicating a potential misunderstanding of the problem's classification.

Raizy
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Homework Statement



A helicopter traveling 130 mph overtakes a speeding car traveling 80 mph. The car had a 0.5-hour head start. How far from the starting point does the helicopter overtake the car?

The answer is 104 miles from the starting point.

Homework Equations



No equations were given, but the book told me to use charts similar to this:

......Rate...*...Time...=Distance (d)
Helicopter...70...t...= 70t
Plane....500...2-t...= 500(2-t)

The Attempt at a Solution



I ended up figuring it out, but world problems like these are still very fuzzy for me. My first attempt went something like this:

Helicopter: 130 * ___ = ___
Car:...80 * 0.5 = 40 mi

I just don't know what to think properly...
 
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You might say x = vt + .5a(t^2), correct?
Use this equation to describe the motion of both the car and the helicopter and maybe you'll be able to figure out how to solve it on your own :smile: In the case of the car, use (t+0.5).
Hint: Let t remain unknown so you can set the equations to equal each other.
Also, make sure you post this next time in Introductory Physics, not precalculus mathematics.
 
Last edited:
Mk said:
You might say x = vt + .5a(t^2), correct?
Use this equation to describe the motion of both the car and the helicopter and maybe you'll be able to figure out how to solve it on your own :smile: In the case of the car, use (t+0.5).
Hint: Let t remain unknown so you can set the equations to equal each other.
Also, make sure you post this next time in Introductory Physics, not precalculus mathematics.

Hey, thanks for the hint and sorry for the rush of a post. I didn't bother to read the forum descriptions...

And back to the question, that's what always got me stuck. I did found out how you had to add the heli's time onto the car, but I always got stuck on how to write the equation.
 
Mk said:
You might say x = vt + .5a(t^2), correct?
No, not at all. As stated in title, this is uniform motion, so the .5 at^2 term is not relevant in this problem.
Mk said:
Use this equation to describe the motion of both the car and the helicopter and maybe you'll be able to figure out how to solve it on your own :smile: In the case of the car, use (t+0.5).

Also, make sure you post this next time in Introductory Physics, not precalculus mathematics.
IMO, this problem could reasonably be posted in either place.
 

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