What should I be thinking about to solve Uniform Motion Problems?

Click For Summary
SUMMARY

The discussion centers on solving uniform motion problems, specifically a scenario where a helicopter traveling at 130 mph overtakes a car traveling at 80 mph, which had a 0.5-hour head start. The solution reveals that the helicopter overtakes the car 104 miles from the starting point. Participants emphasize the importance of using the correct equations for uniform motion, specifically the formula Distance = Rate × Time, and clarify that acceleration terms are irrelevant in this context.

PREREQUISITES
  • Understanding of uniform motion concepts
  • Familiarity with the equation Distance = Rate × Time
  • Basic algebra skills for solving equations
  • Knowledge of introductory physics principles
NEXT STEPS
  • Study uniform motion problems in physics textbooks
  • Practice using the formula Distance = Rate × Time with various scenarios
  • Explore introductory physics resources on motion equations
  • Review the differences between uniform motion and accelerated motion
USEFUL FOR

Students studying physics, particularly those tackling uniform motion problems, as well as educators looking for examples to illustrate these concepts in a classroom setting.

Raizy
Messages
107
Reaction score
0

Homework Statement



A helicopter traveling 130 mph overtakes a speeding car traveling 80 mph. The car had a 0.5-hour head start. How far from the starting point does the helicopter overtake the car?

The answer is 104 miles from the starting point.

Homework Equations



No equations were given, but the book told me to use charts similar to this:

......Rate...*...Time...=Distance (d)
Helicopter...70...t...= 70t
Plane....500...2-t...= 500(2-t)

The Attempt at a Solution



I ended up figuring it out, but world problems like these are still very fuzzy for me. My first attempt went something like this:

Helicopter: 130 * ___ = ___
Car:...80 * 0.5 = 40 mi

I just don't know what to think properly...
 
Physics news on Phys.org
You might say x = vt + .5a(t^2), correct?
Use this equation to describe the motion of both the car and the helicopter and maybe you'll be able to figure out how to solve it on your own :smile: In the case of the car, use (t+0.5).
Hint: Let t remain unknown so you can set the equations to equal each other.
Also, make sure you post this next time in Introductory Physics, not precalculus mathematics.
 
Last edited:
Mk said:
You might say x = vt + .5a(t^2), correct?
Use this equation to describe the motion of both the car and the helicopter and maybe you'll be able to figure out how to solve it on your own :smile: In the case of the car, use (t+0.5).
Hint: Let t remain unknown so you can set the equations to equal each other.
Also, make sure you post this next time in Introductory Physics, not precalculus mathematics.

Hey, thanks for the hint and sorry for the rush of a post. I didn't bother to read the forum descriptions...

And back to the question, that's what always got me stuck. I did found out how you had to add the heli's time onto the car, but I always got stuck on how to write the equation.
 
Mk said:
You might say x = vt + .5a(t^2), correct?
No, not at all. As stated in title, this is uniform motion, so the .5 at^2 term is not relevant in this problem.
Mk said:
Use this equation to describe the motion of both the car and the helicopter and maybe you'll be able to figure out how to solve it on your own :smile: In the case of the car, use (t+0.5).

Also, make sure you post this next time in Introductory Physics, not precalculus mathematics.
IMO, this problem could reasonably be posted in either place.
 

Similar threads

  • · Replies 66 ·
3
Replies
66
Views
5K
  • · Replies 11 ·
Replies
11
Views
4K
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K