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Uniqueness of integers question

  1. Jan 30, 2010 #1
    Find integers s and t such that 1 = 7*s + 11*t. Show that s and t are not unique.

    I can find numbers that satisfy this question, t=2, s=-3 and t=-5, s=8, that show s and t are not unique, but this doesn't seem to be rigorous and I'm not sure where to start with proving this.
  2. jcsd
  3. Jan 30, 2010 #2
    In general there is a theorem which states that for any two relatively prime positive integers a and b there exist integers x and y such that: 1=ax+by. Or, a and b are relatively prime iff there exist integers x and y such that 1=ax+by.
  4. Jan 30, 2010 #3
    yea.. or there exist integers x and y such that (a,b)=ax+by.
  5. Jan 31, 2010 #4
    THis is an even more general result. Namely if L={n|n=ax+by, x,y in Z}, then the smallest element of L is gcd(a,b).
  6. Jan 31, 2010 #5


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    But this is completely correct and a perfectly good solution to this problem. 7(-3)+ 11(2)= -21+ 22= 1, 7(8)+ 11(-5)= 56- 55= 1, and these are two distinct solutions. That is all that is necessary to show that the solution to this particular problem is not unique.
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