Unit conversion difficulties on simple problem

[xgoddess210]

Homework Statement

A 55 g particle is moving to the left at 27 m/s. How much work must be done on the particle to cause it to move to the right at 41 m/s? Answer in joules

Homework Equations

The Attempt at a Solution

27-(-41)=68 , 68*55= 3750

the units here are grams m/s. I need joules. I have no clue on how to make that happen. I can change the g to kg and even get it to Newtons (since I know a joule= Newton-meter) , but I can't take it any farther. Please help!

 

[LowlyPion]

27-(-41)=68 , 68*55= 3750

the units here are grams m/s. I need joules. I have no clue on how to make that happen. I can change the g to kg and even get it to Newtons (since I know a joule= Newton-meter) , but I can't take it any farther. Please help!

Just convert g to kg in your equation is all you need to do.

 

[xgoddess210]

I tried that- It gives me an answer of 3.74, but that is wrong. This doesn't really make sense to me.

 

[PhanthomJay]

Once you have the correct units, your calculation is nonetheless in error. You have $$W = m\Delta v$$ , which is the change in momentum, not the work done. What is the correct equation to use for Work?

 

[xgoddess210]

oh! The equation I have for work is W=Fx, but all that is given to me is two velocities and a mass. Force is m*a so w=m*a*x. I guess I'm still at a loss here.

 

[LowlyPion]

Oops. That's right. I just thought you were converting units wrong like your title was asking.

Overlooked that it was work and that's not work you have.

What about figuring the change in kinetic energy then?

 

[PhanthomJay]

Are you at all familiar with the Work-Energy equation or Conservation of Total Energy equations??